ngql有没有具有类似 sql having语义的用法or关键词

问答 问题
1

MATCH (n0:ip)-[r0 :activeIn]-(n1:equipment)-[r2:login]-(n2: account) return DISTINCT n2.account.accountUuid

如果需要输出的是n1的出入度大于10的，要怎么写ngql？

2

参见 YIELD语句的文档说明

支持对输出结果作计算/过滤

YIELD [DISTINCT] <col> [AS <alias>] [, <col> [AS <alias>] ...]
[WHERE <conditions>];

你这个用例要转换成nGQL的话，需要先做好索引.
用LOOKUP找到出发点, 再用GO语句查询出边. 根据出入点id作分组, 计算出入度作过滤即可.

LOOKUP ON ip
YIELD vertex as v
| GO FROM $-.v over activeIn 
WHERE head(labels($$))  == 'equipment'
YIELD id($$) as dst, id($^) as src
| GROUP BY $-.src, $-.dst YIELD $-.dst as dst WHERE COUNT(*) > 10
| GO FROM $-.dst over login
WHERE head(labels($$)) == 'account'
YIELD DISTINCT properties($$).accountUuid as accountUuid
1 个赞
3

你好 用了你提供的语句发现执行错误 :joy:

4

修改如下:

LOOKUP ON ip YIELD id(vertex) as id
| GO FROM $-.id over activeIn 
WHERE head(labels($$))  == 'equipment' 
YIELD id($$) as dst, id($^) as src
| YIELD $-.src as src, $-.dst as dst, COUNT(*) as degree
| YIELD $-.dst as dst where $-.degree > 10
| GO FROM $-.dst over login 
WHERE head(labels($$)) == 'account' 
YIELD DISTINCT properties($$).accountUuid as accountUuid
2 个赞
6

参考@bofa1ex大佬的语句，最后写出来的是

LOOKUP ON ip YIELD id(vertex) as id
        | GO FROM $-.id over activeIn  REVERSELY
        WHERE head(labels($$))  == 'equipment'
        YIELD id($$) as dst, id($^) as src
        | GO FROM $-.dst over login REVERSELY
        WHERE head(labels($$)) == 'account'
        YIELD id($$) as dst, id($^) as src
        |GROUP BY $-.src YIELD $-.src as src,count($-.src) as degree
        | YIELD $-.src as src where $-.degree > $p0
        | GO FROM $-.src over login REVERSELY
        YIELD properties($$).accountUuid as accountUuid
3 个赞
7

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