如何按照TAG存不存在来删除对应的VERTEX？

[marcus]

• nebula 版本：3.6.0
• 部署方式：分布式
• 安装方式：RPM
• 是否上生产环境：N

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背景：库中有COMPANY、COMPANY1、COMPANY2三类TAG，如何删除那些有COMPANY，而没有COMPANY1标签的节点呢？
eg：
节点1上有标签：COMPANY
节点2上有标签：COMPANY、COMPANY1、COMPANY2
节点3上有标签：COMPANY、COMPANY2
现在按要求是要删除节点1和节点3，这个语句该怎么写？

尝试语句1：
LOOKUP ON COMPANY where ‘COMPANY1’ not in tags(vertex) yield id(vertex) as vv | delete $-.vv
报错：SemanticError: Expression (“INCOMPANY” NOT IN tags(VERTEX)) not supported yet

尝试语句2：
match (n:COMPANY) where ‘COMPANY1’ not in tags(n) with id(n) as rr delete vertex rr
报错：SyntaxError: syntax error near `delete’

[steam]

@marcus

match (n:COMPANY) where ‘COMPANY1’ not in tags(n) with id(n) as rr delete vertex rr

match 要和其他的操作符一起的话，大概得借助 with

[MuYi-方扬]

$vid = (lookup on player yield id(vertex) as id) minus (lookup on team yield id(vertex) as id); delete vertex $vid.id