go语句限制目标节点范围，条件为上一步返回的dst，如何写语句

[laoqi1999]

• nebula 版本：3.6
• 部署方式：单机
• 安装方式： RPM
• 是否上生产环境：N
• 问题的具体描述：
  tag和边的关系如下：
  team–[hasplayer]–>player
  player–[hasfriend]–>player
  查找同一个team下是朋友关系的球员之间的关系。

go 1 step from “team1” over hasplayer yield dst(edge) AS dst |
GO 1 STEPS FROM $-.dst over hasfriend where dst(edge) in (上一步返回的dst) YIELD edge as e

这个sql现在支持吗？该怎么写？

[MuYi]

可以试试

match (v:team)-[:hasplayer]->(p1:player)-[e: hasfriend]->(p2:player)<-[:hasplayer]-(v:team) where id(v) == “team1” return e

[laoqi1999]

@MuYi

match (v:team)-[:hasplayer]->(p1:player)-[e: hasfriend]->(p2:player)<-[:hasplayer]-(v:team) where id(v) == “team1” return e

match可以这么写，但考虑性能，我希望是用go语句，不知道能不能写出来

[ianhe]

GO FROM 'team1' OVER hasplayer YIELD src(edge) as team, edge(edge) as p1 |
GO FROM $-.p1 OVER hasfriend YIELD $-.team as team, src(edge) as p1, dst(edge) as p2 |
GO FROM $-.p2 OVER hasplayer REVERSELY WHERE src(edge) == $-.team YIELD $-.p1 as p1, $-.p2 as p2